整數(shù)序列 已知整數(shù)對(duì)的序列如下:(1,1),(1,2),(2,1),(1,3),(2,2),(3,1),(1,4),(2,3?
已知整數(shù)對(duì)的序列如下:(1,1),(1,2),(2,1),(1,3),(2,2),(3,1),(1,4),(2,3?其規(guī)律為:1.按照兩個(gè)數(shù)的和的大小順序來排列的,(1,1)兩數(shù)的和為2,而(1,2)
已知整數(shù)對(duì)的序列如下:(1,1),(1,2),(2,1),(1,3),(2,2),(3,1),(1,4),(2,3?
其規(guī)律為:1.按照兩個(gè)數(shù)的和的大小順序來排列的,(1,1)兩數(shù)的和為2,而(1,2)(2,1)兩數(shù)的和為3.依次類推可知2.當(dāng)兩數(shù)字的和相等時(shí),是按照前后兩個(gè)數(shù)字的大小來排列的,比如(1,3)(2,2)(3,1)這三個(gè)兩數(shù)字的和都為4,是按照第一個(gè)數(shù)字的大小順序排列的所以按照這個(gè)規(guī)律可以寫出這些數(shù)對(duì)(1,1)(1,2)(2,1)(1,3)(2,2)(3,1)(1,4)(2,3)(3,2)(4,1)(1,5)(2,4)(3,3)(4,2)(5,1)(1,6)(2,5)(3,4)(4,3)(5,2)(6,1)(1,7)(2,6)(3,5)(4,4)(5,3)(6,2)(7,1)(1,8)(2,7)(3,6)(4,5)(5,4)(6,3)(7,2)(8,1)(1,9)(2,8)(3,7)(4,6)(5,5)(6,4)(7,3)(8,2)(9,1)(1,10)(2,9)(3,8)(4,7)(5,6)(6,5)(7,4)(8,3)(9,2)(10,1)(1,11)(2,10)(3,9)(4,8)(5,7)……所以第60個(gè)數(shù)對(duì)應(yīng)該為(5,7)或者這樣找也可以:兩數(shù)和為2,3,4,5,6,7,8,9,10,11,12的數(shù)對(duì)分別有1,2,3,4,5,6,7,8,9,10,11個(gè),且1 2 3 4 5 6 7 8 9 10=55,所以第60個(gè)數(shù)對(duì)應(yīng)該是兩數(shù)字和為12的數(shù)對(duì),且為第5個(gè)所以為(5,7)