冒泡排序java代碼 c#中如何將一個(gè)string數(shù)組轉(zhuǎn)換為int數(shù)組?
c#中如何將一個(gè)string數(shù)組轉(zhuǎn)換為int數(shù)組?首先,您知道如何將int轉(zhuǎn)換為string:使用toString int varint=1string varstring2=變量ToString()
c#中如何將一個(gè)string數(shù)組轉(zhuǎn)換為int數(shù)組?
首先,您知道如何將int轉(zhuǎn)換為string:使用toString int varint=1string varstring2=變量ToString()或轉(zhuǎn)換.toString()int varInt=1字符串varString=轉(zhuǎn)換.ToString(varint)根據(jù)上述轉(zhuǎn)換,可以實(shí)現(xiàn)數(shù)組轉(zhuǎn)換:int[]A1={9,8,7}string[]A2=new string[3]for(int i=0 i&中尉A1。長(zhǎng)度I)a2[I]=a1[I].ToString()