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java怎么去除數(shù)組中重復(fù)的數(shù) VBA中如何利用動態(tài)數(shù)組去除重復(fù)值?

VBA中如何利用動態(tài)數(shù)組去除重復(fù)值?方法1dim a(9) as integrdim b() as integerdim i as integer,j as integerredim preserve

VBA中如何利用動態(tài)數(shù)組去除重復(fù)值?

方法1

dim a(9) as integr

dim b() as integer

dim i as integer,j as integer

redim preserve b(0)

b(0)=a(0)

for i= 1 to ubound (a)

for j= 0 to ubound(b)

if a(i) = b(j) then goto net ,有相同的就跳出

next

redim preserve b(ubound(b) 1)

b(ubound(b))=a(i)

net: ,跳到這里,匹配下一個(gè)數(shù)據(jù)

next

a = b

方法2,有10個(gè)數(shù),先找出最大的數(shù),按照這個(gè)數(shù)定義一個(gè)數(shù)組,把對應(yīng)的值寫入對應(yīng)的元素中,最好先設(shè)置一個(gè)默認(rèn)值

dim a(9) as integer

dim i as integer,temp as integer

temp=a(0)

for i= 1 to ubound(a)

if a(i) > temp then

temp = a(i)

end if

next i

redim b(temp) as integer

for i= 0 to ubound(a)

b(a(i)) = a(i)

next